Quadratic equations?

help plz im stuck on these q's





1.%26gt;(3x-5)(2x+1)=0


2.%26gt;x^3-6x^2+8x=0


3.%26gt;64+x^2=16x


4.%26gt;2x^2-1=14-x


5.%26gt;x^2-(12+x)=0


6.%26gt;x(x+1)+2-5x^2


7.%26gt;(3x-2)(2x+5)=5x^2+5x-18





and im NOT trying to get u to do my homework for me but if u could just do these nd tell me how u did it i would be so thankful





im only 13 and its first time since about 2 months ago so its a little confusing


and theres like 43 other Q's that r hard but if u want to do them for me or just see what they are email me @


flower_power_princess_09@yahoo.com


--~~**~or~**~~--


xxroxy_baybeexx@hotmail.com








P.S. my teacher mr. budlescue is really harsh

Quadratic equations?
look. in 1 you have a product equal to 0.





ab = 0 if and only if a = 0 or b = 0





in your case:





3x - 5 = 0 or 2x + 1 = 0





in other questions, you would have to factorize and follow the steps above. I do not have time for this right now, but please e-mail me all of your questions:


kempos79@yahoo.com and I will try to help you by Sunday.





Cheers,





Kempos
Reply:If I remember this correctly in problem 1. you should set each equation to equal 0, so it would look like 3x-5=0 and 2x+1=0 then solve each one seprately. 3x-5=0 add 5 to each side and you get 3x=5, then divide both sides by 3 and you get x=5/3 then you can simplify. Do the same for the other equation. You will have 2 different answers.